x^2+80x-700=0

Solution for x^2+80x-700=0 equation:

x^2+80x-700=0

a = 1; b = 80; c = -700;
Δ = b2-4ac
Δ = 802-4·1·(-700)
Δ = 9200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9200}=\sqrt{400*23}=\sqrt{400}*\sqrt{23}=20\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-20\sqrt{23}}{2*1}=\frac{-80-20\sqrt{23}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+20\sqrt{23}}{2*1}=\frac{-80+20\sqrt{23}}{2}
$